In this blog you will find the correct answer of the Coursera quiz Solar Energy Basics Coursera Week 5 Quiz mixsaver always try to brings best blogs and best coupon codes
Week- 5
Peer-graded Assignment: Capstone Project
Project Title *
Give your project a descriptive title
|
Capstone Project |
- Site area = 241 m^2
Residential Building
Single Family Home
One floor (Ground floor)
Daily full sun hours=4.4
Average annual sunlight hours=1606 hours / year
Solar Energy Basics
Peer-graded Assignment
Part 2- Calculating electrical load and reducing the load through efficiency improvements
|
Appliances |
No.s |
Power(W) |
Hrs/day |
Days/yr |
Daily Electrical Usage (kWh) |
Annual Electrical Usage (kWh) |
|
Washing machine |
1 |
500 |
1 |
300 |
0.5 |
150 |
|
Tubelights |
5 |
40 |
19 |
350 |
3.8 |
1330 |
|
Television |
1 |
200 |
1 |
200 |
0.2 |
40 |
|
Personal Computer |
1 |
200 |
6 |
260 |
1.2 |
312 |
|
AC |
2 |
1000 |
10 |
120 |
20 |
2400 |
|
Fans |
5 |
35 |
22 |
310 |
3.85 |
1193.5 |
|
Water Heater |
1 |
1500 |
1 |
90 |
1.5 |
135 |
|
CFL Bulbs |
3 |
15 |
3 |
355 |
0.135 |
47.92 |
|
Refrigerator |
1 |
225 |
24 |
360 |
5.4 |
1944 |
Total Daily Electrical Usage For Building (KWh) = 36.585
Total annual electrical usage(KWh) = 7552.425
Efficiency Improvements
|
Appliances |
No.s |
Power(W) |
Hrs/day |
Days/yr |
Daily Electrical Usage (kWh) |
Annual Electrical Usage (kWh) |
|
Washing machine |
1 |
225 |
1 |
300 |
0.26 |
67.5 |
|
LED Tubelights |
5 |
16 |
19 |
350 |
1.52 |
532 |
|
Television |
1 |
200 |
1 |
200 |
0.2 |
40 |
|
Personal Computer |
1 |
200 |
6 |
260 |
1.2 |
312 |
|
AC |
2 |
1000 |
10 |
120 |
20 |
2400 |
|
Fans |
5 |
35 |
22 |
310 |
3.85 |
1193.5 |
|
Water Heater |
1 |
1500 |
1 |
90 |
1.5 |
135 |
|
LED Bulbs |
3 |
10 |
3 |
355 |
0.09 |
31.95 |
|
Refrigerator |
1 |
225 |
24 |
360 |
5.4 |
1944 |
Total Daily Electrical Usage For Building (KWh) = 34.02
Total annual electrical usage (KWh) = 6655.95
Panel power=250 w
Panel area=1.65 m^2
Panel power/Panel area=power/m^2
i.e.panel power/panel area=260w/1.65m^2=151.15w/m^2
Annual solar irradiance at Nellore=5.14KWh/m^2/day
25% loss during pv generation and conversion
conversion efficiency=18%
(Energy demand/Annual full sun hours)/Efficiency=pv system size
Module power=250 watts*4.4 sun hours per day=1100wh/day
Here's a formula for calculating the solar panel's power output.
Solar panel watts x average hours of sunlight x 75% = daily watt-hours.
250 watts x 4.4 hours x .75 = 1100 daily watt hours
System power/Module power=number of modules
1100/250=4.4
Important Links:
- Solar Energy Basics Coursera Week 1 Quiz
- Solar Energy Basics Coursera Week 2 Quiz
- Solar Energy Basics Coursera Week 3 Quiz
- Solar Energy Basics Coursera Week 4 Quiz
